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Therefore, the factored version is:

x²-6x+8 = (x-4)*(x-2)

*x²-6x+8 = (x-4)*(x-2)*

**x²-6x+8 = (x-4)*(x-2)**.

When asked to solve the Quadratic Equation

x²– 6x+8=0 .

we use the above factored version and set each factor equal to 0:

Since x-4=0 we get x=4 ,

and since x-2=0 we get x=2 .

Thus, the 2 zeros are x=4 , x=2

und noch**y = (x-4)*(x-2)**above