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Therefore, the factored version is:
x²-6x+8 = (x-4)*(x-2)x²-6x+8 = (x-4)*(x-2) x²-6x+8 = (x-4)*(x-2) .
When asked to solve the Quadratic Equation
x²– 6x+8=0 .
we use the above factored version and set each factor equal to 0:
Since x-4=0 we get x=4 ,
and since x-2=0 we get x=2 .
Thus, the 2 zeros are x=4 , x=2
und noch y = (x-4)*(x-2) above