Therefore, the factored version is:

 x²-6x+8  = (x-4)*(x-2)  
x²-6x+8 = (x-4)*(x-2) x²-6x+8 = (x-4)*(x-2) .

When asked to solve the Quadratic Equation
x²– 6x+8=0 .

we use the above factored version and set each factor equal to 0:
Since x-4=0 we get x=4 ,
and since x-2=0 we get x=2 .

Thus, the 2 zeros are x=4 , x=2

und noch y = (x-4)*(x-2) above