How to Solve a Quadratic Equation

has the 2 solutions:

Sample Problem: How to solve a Quadratic Equation by Factoring

What are the zeros of $2x^2+5x-3$ ?
It means solving the quadratic equation $2x^2+5x-3=0$ .
The fast way to solve the quadratic equation is by factoring which means to rewrite
$2x^2+5x-3$ as $2(x+p)*(x+q)$
Testing $p=-3$ and $q=.5$ yields indeed
$2x^2+5x-3 = 2(x-3)*(x+0.5)$
implying the two solutions are $x=3$ and $x=-1/2$ .

Using the above Quadratic Equation Calculator to solve $2x^2+5x-3=0$ we must enter the coefficients $a=2, b=5$ and $c=-3$ . With steps we see the two solutions are $x=3$ and $x=-1/2$ .

Get it now? Try the above Quadratic Equation Calculator a few more times.